Find Palindrome Number Program In Java Using For Loop

Find palindrome number program in java using for loop

The word “palindrome” has a Greek origin, a word, number, or set of characters that reads the same forward and backwards. Some examples of a palindrome are MALAYALAM, 343, 2001002, etc. Palindrome in Java can be implemented using many ways. Here we will discuss some important ways:

Using while loops
Using for loops
Using recursion

What is a Palindrome Number?

A Palindrome no. is the number that remains the same when its digits get reversed.

Ex: 15451, for example: If we take 131 and reverse it then after reversing the number remains the same.

Steps to Palindrome Number program

Input the number from the user.
Then Reverse it.
Compare the number with the number entered by the user.
If both the no.’s are the same then print the number as a palindrome
Else print not a palindrome.

Example 1:

Finding Palindrome number Using while loop

Method 1: Check given user input number is Palindrome or not in Java

import java.util.Scanner;
class expalindrome
{
public static void main(String args[])
{
int x,number, y=0,temp=0;
Scanner s=new Scanner(System.in);
System.out.println(“Enter any number: “);
number=s.nextInt();
x=number;
while(number>0)
{
x=number%10;
number=number/10;
temp=temp*10+x;
}
if(temp==y)
{
System.out.println(“Number is Palindrome”);
}
else
{
System.out.println(“not Palindrome”);
}
}
}

Output:

Enter any Number :

161

Number is Palindrome

Example 2:

Finding Palindrome number Using for loop

1) The number is called a palindrome if a number is equal to reverse of its number.

2) For loop repeats rem=num%10; s=(s*10)+rem these steps until num>0. If the condition is false, then it compares the s value with t, if both are equal then it prints the given number is a palindrome.

Method 2: Program to display given user input is Palindrome or not

class Palindrome
{
	public static void main(String arg[])	
	{
	    int num,t,s,rem;
             	    Scanner sc=new Scanner(System.in);
	    System.out.println("Enter any number ");
                   num=sc.nextInt();
	    t=num;
	    for(s=0;num>0;num/=10)
	    {
	    rem=num%10;
	    s=(s*10)+rem;
	    }
	   if(s==t)
		System.out.println(t+" is a palindrome number ");
                  else
		System.out.println(t+" is not a palindrome number ");
                  
	}
}

Output:

Enter any number

161

161 is a palindrome number

Enter any number

1231

1231 is not a palindrome number

Example 3:

Finding Palindrome number Using Using Recursion

1) Using the “Palin” object p, we will call the palindromeOrNot(a) method.

2) The method palindromeOrNot(int num) calls itself as palindromeOrNot(num) until num!=0, if num=0 then it returns sum and sum assigned to s and compares with t, if both are equal then it prints message as “palindrome number”.

Method 3: Program to display given user input is Palindrome or not

class Palin
{
	int sum=0,r;
	int palindromeOrNot(int num)
	{
	    if(num!=0)
	    {
	    r=num%10;
	    sum=(sum*10)+r;
	    num/=10;	
	    palindromeOrNot(num); 
	   }
	return sum;
	}
	public static void main(String arg[])	
	{
	    int a,t,s;
	    Palin p=new Palin();
             	    Scanner sc=new Scanner(System.in);
	    System.out.print("Enter a number :");
                   a=sc.nextInt();
	    t=a;
	    s=p.palindromeOrNot(a);
	    if(s==t)
		System.out.println("Palindrome number ");
                   else
		System.out.println("Not a Palindrome number ");
                  
	}
 
}

Output:

Enter a number :123454321
Palindrome number

Find palindrome number program in java using for loop – Find palindrome number program in java using for loop – Find palindrome number program in java using for loop – Find palindrome number program in java using for loop

TEST

Find palindrome number program in java using for loop